Question

The solubility of oxygen gas in water at 25 °c and 1.0 atm pressure of oxygen is 0.041 g/l. the solubility of oxygen in water at 2.5 atm and 25 °c is

Answer 1

According to Henry's law, solubility is proportional to the external pressure. Since both cases in the problem have the same temperature, only the pressure varies from 1.0 atm to 2.5 atm. This means that just as the pressure is multiplied by a factor of 2.5, we can multiply the solubility by a factor of 2.5 as well. This gives us 0.041 g/L * 2.5 = 0.1025 g/L.

Answer 2

The solubility define as the mixing of the solvent into the solution at constant temperature is called solubility. The solubility of the different compounds is different on the basis of their chemical nature.

Hence, the $0.041 * 2.5 = 0.1025 g/L.$

The correct solubility is 0.1025 g/L.

The solubility depends on these various factors:-

• Temperature
• Pressure

According to Henry's law, solubility is proportional to external pressure and temperature.

Both the cases have the same temperature, only the pressure varies from 1.0 atm to 2.5 atm. This means that just as the pressure is multiplied by a factor of 2.5, we can multiply the solubility by a factor of 2.5 as well.

The solubility is $0.041 * 2.5 = 0.1025 g/L.$

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https://brainly.com/question/22185953