Question

How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

Answer 1

2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g) 

(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
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