Question

What the nth term of 12,17,24,33,44,57,72

Answer 1

$a_1=(1+1)^2+8=2^2+8=4+8=12\\\\a_2=(2+1)^2+8=3^2+8=9+8=17\\\\a_3=(3+1)^2+8=4^2+8=16+8=24\\\\a_4=(4+1)^2+8=5^2+8=25+8=33\\\\a_5=(5+1)^2+8=6^2+8=36+8=44\\\\a_6=(6+1)^2+8=7^2+8=49+8=57\\\\a_7=(7+1)^2+8=8^2+8=64+8=72\\\vdots\\a_n=(n+1)^2+8$