Question

the area of the triangle can be represented by the expression 14x^5+63x^2. if the base is 7x^2, write an expression to represent its height.

Answer 1

The first thing you should know for this case is that the area of a triangle is given by:
 A = (1/2) * (b) * (h)
 Where,
 b: base.
 h: height.
 Clearing the height we have:
 h = ((2) * (A)) / (b)
 Substituting the values
 h = ((2) * (14x ^ 5 + 63x ^ 2)) / (7x ^ 2)
 Simplifying the expression:
 h = ((2) * (2x ^ 3 + 9))
 h = 4x ^ 3 + 18
 answer
 an expression to represent its height is
 h = 4x ^ 3 + 18

Answer 2

An expression that represents the base of the triangle will be $4x^3+18$

The formula for finding the area of a triangle is expressed as:

$A = \frac{bh}{2}$

b is the base of the triangle

h is the height of the triangle

Given the following parameters

$A=14x^5+63x^2\\b=7x^2$

Substitute the given parameters into the formula as shown:

$14x^5+63x^2=\frac{7x^2h}{2}\\2(14x^5+63x^2 )=7x^2h\\28x^5+126x^2 = 7x^2h\\h=\frac{28x^5+126x^2 }{7x^2} \\h=\frac{7x^2(4x^3+18)}{7x^2}\\h=4x^3+18$

Hence an expression that represents the base of the triangle will be $4x^3+18$

Learn more here: https://brainly.com/question/23668009