Consider the gas to be an ideal gas (it will obey all the introductory gas laws). Also you have to note that the gas will not change phase. It won't.
T_s (Temperature Start) = 95.3o C = 95.3 + 273 = 368.3 oK (degrees Kelvin)
T_e (Temperature End) = 0o C + 273 = 273 oK
Initial volume = Vi = 1.55 mL (no need to change to Liters. The answer will be in mL
Vi /Ts = Ve / Vs Ve is the unknown volume that you seek.
1.55 / 368.3 = Ve / 273
Ve = 1.55 * 273 / 368.3
Ve = 1.1489 mL
If your teacher is concerned about Sig digs, then 0.0 has only two.
Your answer should be 1.1 mL, but I'll give you the choice.
