Respuesta :
Answer:
[tex]14 gallons[/tex]
Step-by-step explanation:
Let us suppose that container can hold [tex]x gallon[/tex] water
Initial quantity of water in container = [tex]\frac{1}{6} x[/tex]
Quantity added to the container = [tex]7 gallons[/tex]
Final quantity = [tex]\frac{2}{3} x[/tex]
∴[tex]\frac{2}{3} x - \frac{1}{6} x = 7\\(\frac{2}{3} - \frac{1}{6})x = 7\\\frac{1}{2}x = 7\\x = 7*2\\x = 14[/tex]
Hence the container can hold [tex]14 gallons[/tex] of water
