Respuesta :
20g of TiO2
15.6g of Ti
?g of O2
15.6g*(1mol/47.867g)=0.3259mol Ti
20g*(1mol/(47.867g+32g))=0.2504mol TiO2
xxxxxxxxxx ^ too complicated, doesn't address the question
20g TiO2 - 15.6g Ti = 4.4g O2
final answer 4.4g O2
15.6g of Ti
?g of O2
15.6g*(1mol/47.867g)=0.3259mol Ti
20g*(1mol/(47.867g+32g))=0.2504mol TiO2
xxxxxxxxxx ^ too complicated, doesn't address the question
20g TiO2 - 15.6g Ti = 4.4g O2
final answer 4.4g O2
Answer:
Explanation:
In order to do this, we need first to write the chemical equation that is taking place which is the following:
Ti + O₂ --------> TiO₂
As we can see, the equation is perfectly balanced so, moles of Ti are the same moles TiO₂
To get the grams of O₂, in this simple question, we just need to apply the conservation of mass law, which states that the sum of the mass of the reactants, should be equal to the total mass of the product.
So, if we produced 20 g of TiO₂, which is the only product, then, the sum of the mass of Titanium and oxygen should give 20 g too. So, if we have 15.6 g of Titanium, then the mass of Oxygen:
mO₂ = 20 - 15.6
mO₂ = 4.4 g
This is the mass required to react with Titanium to produce the TiO₂.
