The latent heat of fusion of water at 0 °C is 79.7 calories/g.
This means 79.7 calories are required to melt 1 g of ice.
Thus, calories of heat required to melt 1.52 g of ice cube will be:
[tex]1 g\rightarrow 79.7 calories[/tex]
Thus,
[tex]1.52 g\rightarrow (1.52)(79.7)calories=121.15calories[/tex]
Thus, 121.15 calories are required to melt 1.52 g of ice cubes.