1) Functions given:
x - 7
f(x) = ----------
x + 3
- 3x - 7
g(x) = ------------
x - 1
2)
[tex]f[g(x)]=f[ \frac{-3x-7}{x-1}]= \frac{ \frac{-3x-7}{x-1}-7 }{ \frac{-3x-7}{x-1}+3 } = \frac{ \frac{-3x-7-7x+7}{x-1} }{ \frac{-3x-7+3x-3}{x-1} } = \frac{-10x}{-10} =x[/tex]
3)
[tex]g[f(x)]=g[ \frac{x-7}{x+3}]= \frac{-3[ \frac{x-7}{x+3}]-7}{ \frac{x-7}{x+3}-1 } = \frac{ \frac{-3x+21-7x-21}{x+3} }{ \frac{x-7-x-3}{x+3} }= \frac{-10x}{-10} =x[/tex]
So we have proved that f[g(x)]=g[f(x)]=x