Question

At a private​ school, each​ first-year student is sorted into one of four houses. If 3 students are randomly selected from 15 available students, what is the probability that they are the three youngest students?

Answer 1

3% of 96% i think so

Answer 2

Answer:

The probability that they are the three youngest students is 0.002197.

Step-by-step explanation:

If 3 students are randomly selected from 15 available students, the probability that they are the three youngest students = 1 / 15C3

$15C3=\frac{15!}{3!12!}$

= 455

= $\frac{1}{455}$

= 0.002197