Answer: [tex]0.96\times 10^{23}[/tex] molecules
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
given mass of methyl alcohol = 5.0 g
Molar mass of methyl alcohol = 32.04 g/mol
Putting in the values we get:
[tex]\text{Number of moles}=\frac{5.0g}{32.04g/mol}=0.16moles[/tex]
1 mole of methyl alcohol [tex](CH_3OH)[/tex] contains=6.022\times 10^{23}[/tex] molecules
Thus 0.16 moles of methyl alcohol [tex](CH_3OH)[/tex] contain=[tex]\frac{6.022\times 10^{23}}{1}\times 0.16=0.96\times 10^{23}[/tex]
molecules
Thus there are [tex]0.96\times 10^{23}[/tex] molecules in 5.0 g of methyl alcohol.