A solution was prepared by dissolving 150.0 g of kcl in 295 g of water. calculate the mole fraction of kcl. (the formula weight of kcl is 74.6 g/mol. the formula weight of water is 18.0 g/mol.) express the mole fraction of kcl to two decimal places.
calculate the mole of KCl and water moles of KCl= 150g/74.6g/mol= 2.01 moles moles of water= 295g/18g/mol=16.39 moles calculate the total number of moles 2.01 +16.39 =18.4 moles moles fraction of KCl is therefore=2.01/18.4= 0.11mole
