Respuesta :
area of rectangle is given by:
Area=length×width
given that the area of our rectangle is 24x^6y^15. To get the possible dimensions, we shall factorize the area of our rectangle:
(24x^6y^15)
=(6x^6) by (4y^15)
or
=(8x^6) by (3y^15)
or
=(12x^3x^5) by (2x^3y^10)
Area=length×width
given that the area of our rectangle is 24x^6y^15. To get the possible dimensions, we shall factorize the area of our rectangle:
(24x^6y^15)
=(6x^6) by (4y^15)
or
=(8x^6) by (3y^15)
or
=(12x^3x^5) by (2x^3y^10)
The length of the rectangle with area [tex]24{x^6}{y^{15}}[/tex] is [tex]\boxed{24{x^6}}[/tex] and the width of the rectangle is [tex]\boxed{{y^{15}}}.[/tex]
Further Explanation:
The formula of area of rectangle can be expressed as follows,
[tex]\boxed{Area = \left( l \right) \times \left( w \right)}[/tex]
The formula of perimeter of the rectangle can be expressed as follows,
[tex]\boxed{{\text{Perimeter}} = 2\left( {l + w} \right)}[/tex]
Here, “l” represents the length of the rectangle and “w” represents the width of the rectangle.
Explanation:
The given area of the rectangle is [tex]24{x^6}{y^{15}}.[/tex]
Compare the formula of the rectangle [tex]{\text{Area}= \left( l \right) \times \left( w \right)[/tex] with the given area of the rectangle to obtain the dimensions of the rectangle.
By comparing the length of the rectangle is [tex]24{x^6}}[/tex] and the width of rectangle is [tex]{y^{15}}.[/tex]
The length of the rectangle with area [tex]24{x^6}{y^{15}}[/tex] is [tex]\boxed{24{x^6}}[/tex] and the width of the rectangle is [tex]\boxed{{y^{15}}}.[/tex]
Learn more:
1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function https://brainly.com/question/3412497
Answer details:
Grade: Middle School
Subject: Mathematics
Chapter: Mensuration
Keywords: rectangle, length, width, breadth, area of rectangle, circumference of rectangle, dimensions of rectangle, expression, square.
