stzayas14
stzayas14
21-01-2018
Mathematics
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Find dy/dx when y = cosh (bx^2}
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carlosego
carlosego
21-01-2018
y = cosh (bx^2}
dy/dx= sin
h (bx^2}*( bx^2)'
dy/dx= sinh (bx^2}*( 2bx)
answer
sinh (bx^2}*( 2bx)
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