Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really upset and tosses it at 35 meters per second.
Write an equation to represent the situation above.

I really don't understand, I've been trying to understand it but I honestly can't.

Respuesta :

Y=y1 + v1 + 1/2gt^2

Y= 6m+35m/s^2*t+1/2(9.8m/s^3)t^2

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

[tex] a(t)=9.8 [/tex]

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

[tex] \int \:a\left(t\right)dt=\int \:9.8dt [/tex]

[tex] v(t)=9.8t+C [/tex]

we are given

v(0)=35m/s

we can use it and find C

[tex] v(0)=9.8*0+C [/tex]

[tex] 35=9.8*0+C [/tex]

[tex] C=35 [/tex]

now, we can plug it back

[tex] v(t)=9.8t+35 [/tex]

we know that

integral of velocity is height

we can integrate it again

[tex] \int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt [/tex]

[tex] s(t)=\int \:\left(9.8t+35\right)dt [/tex]

[tex] s(t)=4.9t^2+35t+C [/tex]

now, we have

s(0)=6

we can use it and find C

[tex] s(0)=4.9(0)^2+35(0)+C [/tex]

[tex] 6=4.9(0)^2+35(0)+C [/tex]

now, we can plug back C

[tex] C=6 [/tex]

and we get

[tex] s(t)=4.9t^2+35t+6 [/tex].............Answer

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