Use the Pythagorean theorem:
[tex]a^2+b^2=c^2[/tex]
c - a hypotenuse
a, b - legs
We have: a = 9 and c = 12. Substitute:
[tex]9^2+b^2=12^2[/tex]
[tex]81+b^2=144[/tex] subtract 81 from both sides
[tex]b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}[/tex]
A Pythagorean triple consists of three positive integers a, b and c, such that
[tex]a^2+b^2=c^2[/tex].
[tex]b=3\sqrt{7}[/tex] is not positive integer.