Question

Evaluate the logarithm log525

Question 6 options:

1

5

-2

2

Answer 1

I think the question is to evaluate the logarithm of 25 on basis 2.

This is:

$log_5 25=log_5(5^2)=2log_55=2(1)=2$

I used these propertites:

$1)log_b(a^n)=nlog_ba 2)log_aa=1$

Answer: 2

Answer 2

Answer:

$log_{5}(25)$ =1.

Step-by-step explanation:

Given  : $log_{5}(25)$.

To find : Evaluate the logarithm.

Solution : We have given  $log_{5}(25)$.

We can write the 25 as $5^{2}$.

Then $log_{5}(5^{2})$.

By the logarithm rule :

(i)$log_{x}(x^{n})$ =  $nlog_{x}(x)$.

(ii) $log_{x}(x)$ =  1.

Here x = 5 , n=  2.

$log_{5}(5^{2})$ = $2log_{5}(5)$.

$2log_{5}(5)$

$log_{5}(5)$ = 1.

2* 1 = 2.

Therefore,  $log_{5}(25)$ =1.