Answer is: 127Â grams of metallic copper
Chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54 g.
m(CuSOâ‚„) = 319 g.
m(Cu) = ?
n(Al) = 54 g ÷ 27 g/mol
n(Al) = 2 mol.
n(CuSO₄) = 319 g ÷159,5 g/mol.
n(CuSOâ‚„) = 2 mol, limiting reagens.
from reaction n(CuSOâ‚„) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
m(Cu) = 2 mol · 63,5 g/mol.
m(Cu) = 127 g.