A 100-n force has a horizontal component of 80 n and a vertical component of 60 n. the force is applied to a box which rests on a level frictionless floor. the cart starts from rest, and moves 2.0 m horizontally along the floor. what is the cart's final kinetic energy?
For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance:
80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.
So the cart has a final kinetic energy of 160 Joules.
