Answer:
(x, y) = (7, -5)
Step-by-step explanation:
It generally works well to follow directions.
The matrix of coefficients is ...
[tex]\left[\begin{array}{cc}2&4\\-5&3\end{array}\right][/tex]
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
[tex]\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right][/tex]
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)
