Question

A racing car is traveling on a circular race course of radius 569 m at a speed such that it makes 1.46 rev in 1 minute. the mass of the car is 1550 kg. what is the centripetal force acting on the car? answer in units of n.

Answer 1

1.46rev in 1min = 2pi*1.46revs/60s=0.152891 rad/s=ω
Fc=m*r*ω^2
Fc= 1550kg*(0.152891)^2 * 569m = 19951N 

hope this helps! Thanks!

Answer 2

The centripetal force acting on the car in Newton is equal to 20,618.59 Newton.

Given the following data:

• Radius = 569 meters.

• Angular speed = 1.46 rev/min

• Mass of car = 1550 kg.

Conversion:

Angular speed = 1.46 rev/min to rad/s = $1.46 \times \frac{2\pi}{60} = 0.1529\;rad/s$

To determine the centripetal force acting on the car in Newton:

Mathematically, centripetal force is given by the formula:

$F_c = mr\omega^2$

Substituting the given parameters into the formula, we have;

$F_c =1550 \times 569 \times (0.1529)^2$

Centripetal force = 20,618.59 Newton.

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