A car traveling at 7.0 m/s accelerates uniformly at 2.5 m/s2 to reach a speed of 12.0 m/s. how long does it take this acceleration to occur

Respuesta :

Vf=Vi+at
12=7+2.5t
5=2.5t
t=2s

We have that A car traveling at 7.0 m/s accelerates uniformly at 2.5 m/s2 to reach a speed of 12.0 m/s has t accelerate

t=2s

From the question we are told that

A car traveling at 7.0 m/s

accelerates uniformly at 2.5 m/s2

a speed of 12.0 m/s.

Generally the Newton equation for the distance  is mathematically given as

a=\frac{v-u}{t}

t=\frac{12-7}{2.5}

t=2s

Therefore

car traveling at 7.0 m/s accelerates uniformly at 2.5 m/s2 to reach a speed of 12.0 m/s has t accelerate

t=2s

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