Respuesta :

Find the slope of line 1
m₁ = 3/4

Find the slope of line 2 (perpendicular to line 1)
m₁ × m₂ = -1
3/4 × m₂ = -1
m₂ = -4/3

Find the line equation with m = -4/3 and pass through (-12,10)
y - y₁ = m(x - x₁)
y - 10 = -4/3 (x + 12)
y - 10 = -4/3 x - 16
y = -4/3 x - 6
cher

Slope intercept form : y=mx+b , where m=slope, y=y-intercept


Perpendicular to : y = 3/4x - 2 ; Passes through (-12, 10)


**Remember : When finding the slope of a perpendicular line, we must get the negative reciprocal **


Ex of negative reciprocal : 3/2 → -2/3


The original line has a slope of 3/4, therefore our perpendicular slope is -4/3


Now we have to use the point-slope formula to find our new equation.


y - y₁ = m(x - x₁)


Passes through (-12, 10) ; slope = -4/3


y₁ = 10 ; x₁ = -12


Simply plug in the numerals for y₁ and x₁ as well as m.

y - (10) = -4/3(x - (-12))


Simplify.


y - 10 = -4/3(x + 12)


Simplify.


y - 10 = -4/3x - 48/3


Simplify -48/3


-48/3 = -16


y - 10 = -4/3 - 16


Now, we need to put this into slope-intercept form.


**Remember : slope intercept form is y=mx+b where m=slope, y=y-intercept**


So, add 10 to both sides.


y = -4/3x - 16 + 10


Simplify.


y = -4/3x - 6


~hope I helped!~

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