Respuesta :
Find the slope of line 1
m₁ = 3/4
Find the slope of line 2 (perpendicular to line 1)
m₁ × m₂ = -1
3/4 × m₂ = -1
m₂ = -4/3
Find the line equation with m = -4/3 and pass through (-12,10)
y - y₁ = m(x - x₁)
y - 10 = -4/3 (x + 12)
y - 10 = -4/3 x - 16
y = -4/3 x - 6
m₁ = 3/4
Find the slope of line 2 (perpendicular to line 1)
m₁ × m₂ = -1
3/4 × m₂ = -1
m₂ = -4/3
Find the line equation with m = -4/3 and pass through (-12,10)
y - y₁ = m(x - x₁)
y - 10 = -4/3 (x + 12)
y - 10 = -4/3 x - 16
y = -4/3 x - 6
Slope intercept form : y=mx+b , where m=slope, y=y-intercept
Perpendicular to : y = 3/4x - 2 ; Passes through (-12, 10)
**Remember : When finding the slope of a perpendicular line, we must get the negative reciprocal **
Ex of negative reciprocal : 3/2 → -2/3
The original line has a slope of 3/4, therefore our perpendicular slope is -4/3
Now we have to use the point-slope formula to find our new equation.
y - y₁ = m(x - x₁)
Passes through (-12, 10) ; slope = -4/3
y₁ = 10 ; x₁ = -12
Simply plug in the numerals for y₁ and x₁ as well as m.
y - (10) = -4/3(x - (-12))
Simplify.
y - 10 = -4/3(x + 12)
Simplify.
y - 10 = -4/3x - 48/3
Simplify -48/3
-48/3 = -16
y - 10 = -4/3 - 16
Now, we need to put this into slope-intercept form.
**Remember : slope intercept form is y=mx+b where m=slope, y=y-intercept**
So, add 10 to both sides.
y = -4/3x - 16 + 10
Simplify.
y = -4/3x - 6
~hope I helped!~