Respuesta :
Refer to the attached image.
AB is the distance traveled after taking slightly right onto Oak Avenue from Main street = 4 miles
BC is the distance traveled by taking a 90 degree left turn onto Lilac Lane = x miles.
Lilac Lane intersects Main Street at 30 degrees for the end of the detour, which is AC.
Now we have to find the distance traveled travel on Lilac Lane to reach Main Street = BC=x
Now, in triangle ABC,
by angle sum property,
[tex] \angle A+\angle B+\angle C=180^{\circ} [/tex]
[tex] \angle A+90^{\circ}+30^{\circ}=180^{\circ} [/tex]
[tex] \angle A=60^{\circ} [/tex]
Now in triangle ABC,
Consider [tex] \sin 30^{\circ} = \frac{Perpendicular}{Hypotenuse} [/tex]
[tex] \sin 30^{\circ} = \frac{AB}{AC} [/tex]
[tex] \frac{1}{2} = \frac{4}{AC} [/tex]
AC = 8 miles.
Now consider,
[tex] \sin 60^{\circ}=\frac{BC}{AC} [/tex]
[tex] \frac{\sqrt{3}}{2}=\frac{x}{8} [/tex]
[tex] \frac{8\sqrt{3}}{2}= x [/tex]
[tex] x = 4\sqrt{3} [/tex]
x = 6.92 miles
So, 6.92 miles should be traveled on Lilac Lane to reach Main Street.
