Question

The axis of symmetry for the graph of the function is f(x) = 1/4x^2 + bx + 10 is x = 6. What is the value of b?

Answer 1

x-coordinate of vertex (or axis of symmetry) of a quadratic function f(x)=ax2+bx+c is given as:
x=−b2a=−b12=−2b-2b = 6 --> b=6−2=−3
b = -3