1. x + 3y = 3 and x - 2y = 0
2. (2,1)
3. solution
4. true
5. equation 1 : equation 2 :
x + y = 3 x - 2y = 0
2 + 1 = 3 2 - 2(1) = 0
3 = 3 (correct) 2 - 2 = 0
0 = 0 (correct)
both equations are true...so (2,1) is a solution set to this system of equations
