Question

The length of a rectangle is 3 yd less than twice the width, and the area of the rectangle is 44 yd2 . find the dimensions of the rectangle.

Answer 1

A = L * W
A = 44
L = 2W - 3

44 = W(2W - 3)
44 = 2W^2 - 3W
-2W^2 + 3W + 44 = 0
(-2W + 11)(W + 4) = 0

W + 4 = 0
W = -4......not this one because it is negative

-2W + 11 = 0
-2W = -11
W = -11/-2
W = 5.5 <=== width is 5.5 yds

L = 2W - 3
L = 2(5.5) - 3
L = 11 - 3
L = 8 <=== length is 8 yds