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Diagonal = ?
Wide = 20 in.
High = 15 in.
Pythagoras formula: D² = H² + W²
[tex]D^2=(15)^2+(20)^2\\ \\D^2=225+400\\ \\D^2=625\\ \\D= \sqrt{625}\\ \\D=25\ in.\quad\Longrightarrow\boxed{\boxed{\mathbb{ANSWER\ \checkmark}}}\\ \\ \\\textbf{HOPE\ THIS\ HELPS...!!}[/tex]
Diagonal = ?
Wide = 20 in.
High = 15 in.
Pythagoras formula: D² = H² + W²
[tex]D^2=(15)^2+(20)^2\\ \\D^2=225+400\\ \\D^2=625\\ \\D= \sqrt{625}\\ \\D=25\ in.\quad\Longrightarrow\boxed{\boxed{\mathbb{ANSWER\ \checkmark}}}\\ \\ \\\textbf{HOPE\ THIS\ HELPS...!!}[/tex]
The diagnal should be 25 inches long. Hope this helps!