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The following graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k: a parabola with a vertex of 2, 3 What is the value of k?

Respuesta :

We are given

[tex]f(x)=x^2[/tex]

and it has been shifted to get form

[tex]f(x)=(x-h)^2+k[/tex]

where

vertex is (h,k)

and we are given vertex as (2,3)

now, we can compare

[tex](h,k)=(2,3)[/tex]

and then we can solve for k

and we get

[tex]k=3[/tex]..............Answer

The value of [tex]k[/tex] is [tex]3[/tex] in the equation of the parabola [tex]f(x)=(x-h)^2+k[/tex] with the vertex at [tex](h,k)[/tex].

The given function of the curve is [tex]f(x)=x^2[/tex] which is being shifted to  [tex]f(x)=(x-h)^2+k[/tex] with the vertex at [tex](h,k)[/tex].

According to the question, [tex](2,3)[/tex] is the vertex of the parabola.

So, compare the parametrs,

[tex](h,k)\rightarrow (2,3)\\h=2\\k=3[/tex]

Hence, the value of [tex]k[/tex] is [tex]3[/tex] in the equation of the parabola [tex]f(x)=(x-h)^2+k[/tex] with the vertex at [tex](h,k)[/tex].

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