Question

How much of the 8% solution should we use to make 100g of a 3% solution?

Answer 1

suppose x grams of 8% solution should be mixed to make 100 g of 3% solution.
here we shall have:
the amount of 3% solution in the 100 g will be:
3/100*100=3 grams
the the equation will be, 8% of what quantity becomes 3g?
(8/100)*x=3
hence solving for x we shall have:
0.08x=3
x=3/0.08
x= 37.8 grams
The implication of this is that, when you have 37.5 grams of 8% solution, that will contain 3  of pure chemical and hence when you add more solvent on top of 37.5 g until you reach 100g, that will be 3% solution.

Answer 2

The mass of 8% that will be required to make 100 g of the 3% solution is 37.5 g.

The given parameters:

• mass of the given solution, m = 100 g
• concentration of the solution, = 3%

The mass of the 3% of the given solution is calculated as follows;

m = 0.03 x 100

m = 3 g

The mass of 8% that will be required to make 100 g of the 3% solution is calculated as follows;

0.08x = 3

$x = \frac{3}{0.08} \\\\x = 37.5 \ g$

Thus, the mass of 8% that will be required to make 100 g of the 3% solution is 37.5 g.

Learn more about percentage here:https://brainly.com/question/1929664