Question

Agent bourne transferred classified files from the cia mainframe into his flash drive. the drive had 36.536.536, point, 5 megabytes on it before the transfer, and the transfer happened at a constant rate. after 125125125 seconds, there were 549549549 megabytes on the drive. the drive had a maximum capacity of 100010001000 megabytes. what was the speed of the transfer?

Answer 1

For this case, the first thing you should know is that the speed of the transfer is given by
 Speed = Megabytes / time
 Substituting
 V = (549) / (125)
 V = 4.392 mb / s
 answer
 the speed of the transfer was 4,392 mb / s

Answer 2

Answer: $4.1\text{ megabytes per second}$

Step-by-step explanation:

Given: Initial load of megabytes in his flash drive before transfer = 36.5 MB

Final load of megabytes in his flash drive after transfer = 549 MB

The increase in load =$549-36.5=512.5\ MB$

Time taken to transfer files = 125 seconds

The speed of transfer is the rate of change of load by with respect to time.

Thus, $\text{speed}=\frac{\text{increase in load }}{\text{Time}}$

$=\frac{512.5}{125}=4.1\text{ megabytes per second}$