Respuesta :
1 book is 17.55
2 books is 16.70
3 books is 15.85
4 books is 15
5 books is 4.15
6 books is 4.30
7 books is (3.55)
2 books is 16.70
3 books is 15.85
4 books is 15
5 books is 4.15
6 books is 4.30
7 books is (3.55)
The cost for each book will be [tex]\boxed{\$ 12.45}[/tex] if the person buy 7 books.
Further explanation:
The arithmetic sequence can be expressed as follows,
[tex]{a_1}, {a_2}, {a_3}[/tex]......
Here,[tex]a{\text{ or }}{a_1}[/tex] represents the first term, [tex]{a_2}[/tex] represents the second term, and so on.
The common difference “d” can be obtained as follows,
[tex]\boxed{d = {a_2} - {a_1}}[/tex]
The nth term can be obtained as follows,
[tex]\boxed{{a_n} = a + \left( {n - 1} \right)d}[/tex]
Explanation:
The cost of a book is [tex]\$ 17.55.[/tex]
The cost of a book is [tex]\$ 16.70[/tex] if the person buys 2 books.
The cost of a book is [tex]\$ 15.85[/tex] if the person buys 3 books.
The cost of a book is [tex]\$ 15.00[/tex] if the person buys 4 books.
The sequence is [tex]\$ 17.55, \$ 16.70, \$ 15.85, \$ 15.00.[/tex]
The first term is [tex]\$ 17.55,[/tex] the second term is [tex]\$ 16.70.[/tex]
The common difference “d” can be obtained as follows,
[tex]\begin{aligned}d&={a_2} - {a_1}\\&=16.70 - 17.55\\&=- 0.85\\\end{aligned}[/tex]
The cost for each book if the person buys 7 books can be obtained as follows,
[tex]\begin{aligned}{a_6}&= 17.55 + \left( {7 - 1} \right)\left( { - 0.85} \right)\\&= 17.55 + 6\left({ - 0.85} \right)\\&= 17.55 - 5.1\\&=\$12.45\\\end{aligned}[/tex]
The cost for each book will be [tex]\boxed{\$ 12.45}[/tex] if the person buy 7 books.
Learn more:
1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function https://brainly.com/question/3412497
Answer details:
Grade: Middle School
Subject: Mathematics
Chapter: Arithmetic Sequence
Keywords: Store, books, price, $17.55, 2 books, 3 books each cost $16.40, pattern continues, cost, 7 books.