Question

ten plus eight times a number a equals eleven times another number d minus six solve for a

Answer 1

So your equation would be 8a+10=11d-6 First: you would combine like terms so normally you would take away the smaller number. So to cancel out the negative 6 you added you add positive six to the negative 6 so you would get 0 and whatever you do to one side you have to do to the other so you would do 10 + 6. Your new equation would be 8a+16=11d. Now you do -16 to both sides. So your new equation would be 8a= 11d - 16. Now you divide by 8. So your final equation would be a=11d-2.

Answer 2

Answer:

$a=\frac{11d-16}{8}$

Step-by-step explanation:

We have been given a word phrase. We are asked to write an equation and solve for 'a'.

Eight times the number 'a' would be $8a$.

Ten plus eight times a number 'a' would be $10+8a$.

Eleven times another 'd' would be $11d$.

Eleven times another 'd' minus six would be $11d-6$.

Equate both expression:

$10+8a=11d-6$

$10-10+8a=11d-6-10$

$8a=11d-16$

$\frac{8a}{8}=\frac{11d-16}{8}$

$a=\frac{11d-16}{8}$

Therefore, the value of 'a' is $\frac{11d-16}{8}$.