Respuesta :
Since the person didn't write the answer choices they were:
A. On average, city A was warmer than city B.
B. The median and mode are different for city B.
C. The temperature range between the maximum and minimum values for city A is greater than the temperature range between the maximum and minimum values for city B.
D. The median is less for city A than for city B.
I believe it is A personally cause i took the test and got it right
Answer:
- On average city A is warmer than city B
- The median and mode are same for city B.
- The temperature range between the maximum and minimum values for city B is greater than the temperature range between the maximum and minimum values for city A.
- The median is less for city B than for city A.
Step-by-step explanation:
We are given the following information in the question:
City A: 90 85 84 85 80 82 83 85 89 82
City B: 77 78 98 91 78 76 78 85 84 71
Formula:
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}[/tex]
Mode is the most frequent observation
City A:
[tex]Mean =\displaystyle\frac{845}{10} = 84.5[/tex]
Median:
Sorted data: 80, 82, 82, 83, 84, 85, 85, 85, 89, 90
Median = [tex]\frac{84+85}{2} = 84.5[/tex]
Mode = 85
Minimum = 80
Maximum = 90
Range = Maximum - Minimum = 10
City B:
[tex]Mean =\displaystyle\frac{816}{10} = 81.6[/tex]
Median:
Sorted data: 71, 76, 77, 78, 78, 78, 84, 85, 91, 98
Median = [tex]\frac{78+78}{2} = 78[/tex]
Mode = 78
Minimum = 71
Maximum = 98
Range = Maximum - Minimum = 27
Thus, we can say that:
- On average city A is warmer than city B
- The median and mode are same for city B.
- The temperature range between the maximum and minimum values for city B is greater than the temperature range between the maximum and minimum values for city A.
- The median is less for city B than for city A.