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How many days will it take a spaceship to accelerate from rest to the speed of light (3.0Ã108m/s) with the acceleration g?

Respuesta :

Dejanras
Answer is: 354 days.
V = V₀ + g·t.
V - final velocity, V = 3·10⁸ m/s.
V₀ - initial velocity, V₀ = o, because spaceship is in rest.
t - time, how long it takes for spaceship to move from one position to another.
g - gravity, g = 9,8 m/s².
t = V÷g = 3,06·10⁷s = 510204min = 88503,4hr = 354 days.

adioabiola

The number of days it takes a spaceship to accelerate from rest to the speed of light (3.0×10⁸m/s) is; 354.3 days.

Acceleration and Speed

The number of days it takes the spaceship to accelerate can be calculated from the equation of motion as follows;

  • V = U + g(t)

Where, V = final velocity = 3.0×10⁸m/s

  • U = initial velocity = 0m/s

  • g = acceleration due to gravity = 9.8m/s

  • t = time taken in seconds= ?.

Hence,

  • 3.0×10⁸ = 0 + 9.8t

  • t = 3.0×10⁸/9.8

  • t = 30612244 seconds

Hence, since 86400 seconds make one day;

t = 30612244/86400 = 354.3 days.

Read more on speed and acceleration;

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