Question

Help with homework Algebra 2:
What is the quotient (72y3 + 12y2 − 30y) ÷ 6y?

12y2 − 2y + 5
12y2 + 2y − 5
12y3 + 2y2 − 5y
12y2 − 2y − 5

Answer 1

The answer is 12y^2 + 2y - 5
The solution:
(72y^3 + 12y^2 - 30y) / 6y =
(6y)*(12y^2 + 2y - 5) / 6y = 12y^2 + 2y - 5

Answer 2

Answer:

$12y^2+2y-5$

Step-by-step explanation:

$(72y^3 + 12y^2 - 30y)$ ÷ 6y

WE divide each term by 6y, while dividing by 6y we apply property of exponent

a^m / a^n= a^m-n

$\frac{72y^3}{6y} =12y^2$

$\frac{12y^2}{6y} =2y$

$\frac{30y}{6y} =5$

Now we combine all the terms

$12y^2+2y-5$