Respuesta :
12•x+8.50•y>=1,000
x+y=<200
X-number of tickets sold at the door
Y-number of tickets sold in advance
x+y=<200
X-number of tickets sold at the door
Y-number of tickets sold in advance
As per the problem
The auditorium hold 200 people.
Also the tickets cost $12 at the door and $8.50 if purchased in advance.
The drama club has a goal of selling at least $1000 worth of tickets to Saturday's show.
Let total number of tickets purchased at door be x and the number of tickets purchased in advance be y.
Then revenue for x tickets =12x
Revenue from y tickets=8.50y
Hence the inequality can be set up as below
[tex] x+y\leq 200, \text{ Because the maximum capacity is 200} [/tex]
[tex] 12x+8.50y\geq 1000 [/tex]
[tex] x>0,y>0 [/tex]