Respuesta :
The first pair of triangles are similar.
Triangle ABC is similar to Triangle PQR.
I used the SSS theorem of congruency.
( side - side - side) since I knew the sides were equal I knew that they were congruent.
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The second pair of triangles are similar too.
Triangle ABC is similar to Triangle DEF.
I also used the SSS theorem of congruency.
Since I knew what the sides were, I did some calculations and they all equalled 6...
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I hope that helps you out!! Any more questions??
Triangle ABC is similar to Triangle PQR.
I used the SSS theorem of congruency.
( side - side - side) since I knew the sides were equal I knew that they were congruent.
----------------------------------------------------------
The second pair of triangles are similar too.
Triangle ABC is similar to Triangle DEF.
I also used the SSS theorem of congruency.
Since I knew what the sides were, I did some calculations and they all equalled 6...
----------------------------------------------------------
I hope that helps you out!! Any more questions??
Answer: Both the pairs of triangles (a) and (b) are similar.
(a) By AA similarity statement.
(b) By proportionality statement.
Step-by-step explanation: We are given to check whether the pairs of triangles in cases (a) and (b) are similar or not.
(a) We see that in triangles ABC and PQR, we have
m∠A = m∠P = 41°, m∠B = m∠Q = 85° and m∠C = m∠R = 54°.
So, ΔABC and ΔPQR are similar by AA similarity statement.
(b) We see that in triangles ABC and DEF, we have
AB = 4, BC = 5, CA = 3, DE = 24, EF = 30 and FD = 18.
So, we have
[tex]\dfrac{DE}{AB}=\dfrac{EF}{BC}=\dfrac{FD}{CA}=6.[/tex]
That is, the corresponding sides of two triangles are proportional.
Thus, ΔABC and ΔDEF are similar by proportionality statement.