Question

please anyone help
p=$\frac{q ^{2} }{r}$

q=5.46 to 3 significant figures
r=17.74 to 4 significant figures.
by considering bounds, work out the value of p to a suitable degree of accuracy.
you must give a reason to the answer

Answer 1

5.46 to 3 sig figs means the range is {5.455,5.465} and 17.74 means the range {17.735,17.745}.
p=q²/r has a maximum value when q=5.465 and r=17.735 and a minimum value when 5.455 and r=17.745.
So the range of p is 1.6769 to 1.6840. When we have 2 decimal places we get p=1.68 which accommodates the maximum and minimum values of the range. So 2 decimal places is a suitable degree of accuracy, or we could say 3 significant figures.

Answer 2

The value of p based on the information given will be 1.6805.

How to compute the value?

From the information given, the following can be deduced:

q = 5.46

r = 17.74

p = q²/r

p = (5.46)²/17.74

p = 29.8116/17.74

p = 1.6805

Therefore, p is 1.6805.

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