Respuesta :
Let x be the number of bracelets that the artiste can make.
We know the following constraint :
[tex]8x\leq15,3x\leq86,4x\leq92,x\leq17[/tex]
We solve like this:
[tex]x\leq\frac{15}{8},x\leq\frac{86}{3},x\leq\frac{92}{4},x\leq17 \\x\leq1.8,x\leq12,x\leq23.5,x\leq17[/tex]
Since the lowest value is 1.5, so the artiste can make up to one bracelet.
We know the following constraint :
[tex]8x\leq15,3x\leq86,4x\leq92,x\leq17[/tex]
We solve like this:
[tex]x\leq\frac{15}{8},x\leq\frac{86}{3},x\leq\frac{92}{4},x\leq17 \\x\leq1.8,x\leq12,x\leq23.5,x\leq17[/tex]
Since the lowest value is 1.5, so the artiste can make up to one bracelet.
Due that the artist needs 8 orange beads per each bracelet and he only have 15 beads of this color, he only could form 1 bracelet.
After finish the first bracelet, only left 7 orange beads (15 - 8), which are not enough for form another one.
After finish the first bracelet, only left 7 orange beads (15 - 8), which are not enough for form another one.