Question

A jury consists of five men and seven women. three are selected at random for an interview find the probability that all three are men.

Answer 1

There are 5+7 = 12 total people. 
The probability that the first person picked is a man is 5/12. 
P{2nd person picked is also a man} = 4/11
 P(3rd person is also a man) = 3/10
 P{all 3 are men} = (5/12)(4/11)(3/10) = 60/1320 = 1/22 = 0.04545