katertot2
katertot2 katertot2
  • 31-12-2017
  • Mathematics
contestada

Change the fraction 3/(x +9) to one having 2x^2 +13x - 45 for its denominator.

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tynollette tynollette
  • 31-12-2017
2x²+13x-45 =(x+9)(2x-5)
3/(x+9)=[3(2x-5)]/[(x+9)(2x-5)]=(6x-15)/(2x²+13x-45) 
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