Question

Find the point on the line y=x+1 that is closest to the point (4 1)

Answer 1

$d = \frac{4}{ \sqrt{2} } = 2 \sqrt{2}$
$\sqrt{ {(x - 4)}^{2} + {x}^{2} } = 2 \sqrt{2} \\ x = 2$
point
$(2 \: 3)$