Answer:
[tex]G^{-1}(G(x))=x[/tex]
Step-by-step explanation:
Definition: Let f be one-to-one function with the domain A and the range B. Then the inverse function [tex]f^{-1}[/tex] has the domain B and the range A and is defined as
[tex]f^{-1}(y)=x\ \Leftrightarrow \ f(x)=y[/tex]
Facts:
1) For every [tex]x\in A:[/tex]
[tex]f^{-1}(f(x))=x[/tex]
2) For every [tex]y\in B:[/tex]
[tex]f(f^{-1}(y))=y[/tex]
So, [tex]G^{-1}(G(x))=x[/tex]