For clarification, I will put how IveĀ interpreted this equation: [tex]8x-2x+2= \frac{1}{3}(9x+3)+7 [/tex] This can be solved by simplifying and rearranging: [tex]6x+2= \frac{9x}{3}+ \frac{3}{3}+7 \\ 6x+2=3x+1+7 \\ 3x+2=8 \\ 3x=6 \\ \boxed{x=2} [/tex]