Respuesta :
Answer:
If you are doing it on USATestPrep, the answer is
D) R= Square root of A over \pi and plus r^2
The Square root goes all the way
I hope this helped ;)
ANSWER
[tex]R = \pm \sqrt{\frac{A+\pi r^2}{ \pi}}[/tex]
EXPLANATION
We want to rearrange the formula,
[tex]A=\pi(R^2-r^2)[/tex]
for
[tex]R.[/tex]
This means that, we will isolate
[tex]R[/tex]
so that, it will be on one side of the equation, while the others are also on the other side of the equation.
We must first divide through by π to obtain,
[tex] \frac{A}{ \pi} =R^2-r^2[/tex]
We add
[tex] {r}^{2} [/tex]
to both sides to obtain,
[tex] \frac{A}{ \pi} + {r}^{2} =R^2[/tex]
We now take the square root of both sides to obtain,
[tex] \pm \sqrt{\frac{A}{ \pi} + {r}^{2}} =R[/tex]
We simplify further to obtain,
[tex]R = \pm \sqrt{\frac{A+\pi r^2}{ \pi}}[/tex]
[tex]R = \pm \sqrt{\frac{A+\pi r^2}{ \pi}}[/tex]
EXPLANATION
We want to rearrange the formula,
[tex]A=\pi(R^2-r^2)[/tex]
for
[tex]R.[/tex]
This means that, we will isolate
[tex]R[/tex]
so that, it will be on one side of the equation, while the others are also on the other side of the equation.
We must first divide through by π to obtain,
[tex] \frac{A}{ \pi} =R^2-r^2[/tex]
We add
[tex] {r}^{2} [/tex]
to both sides to obtain,
[tex] \frac{A}{ \pi} + {r}^{2} =R^2[/tex]
We now take the square root of both sides to obtain,
[tex] \pm \sqrt{\frac{A}{ \pi} + {r}^{2}} =R[/tex]
We simplify further to obtain,
[tex]R = \pm \sqrt{\frac{A+\pi r^2}{ \pi}}[/tex]