Question

What is the density of a mineral with a mass of 41.2 g and a volume 8.2 cm3?

Answer 1

hey there!:

mass = 41.2 g

Volume = 8.2 cm³

Therefore:

D = m / V

D = 41.2 / 8.2

D = 5.02 g/cm³

Answer 2

Answer : The density of a mineral is, 5.024 g/ml

Solution : Given,

Mass of mineral = 41.2 g

Volume of mineral = $8.2cm^3=8.2ml$      $(1cm^3=1ml)$

Formula used :

$Density=\frac{Mass}{Volume}$

Now put all the given values in this formula, we get the density of mineral.

$Density=\frac{41.2g}{8.2ml}=5.02g/ml$

Therefore, the density of a mineral is, 5.024 g/ml