Question

By the end of a year,Kieran's savings is 9/2 of Simons savings(a) what is the ratio of Kieran's savings to Simons savings to their total savings? (b) How many times the total amount of money saved is Kieran's savings?(c)How many times the total amount of money saved is Simon's savings?(d)Simon saves$28 less than Kieran.How much do both of them save altogether?

Answer 1

K=9S/2, total savings is S+9S/2=11S/2. So 9S/2÷11S/2=9/11. (a) The ratio is 9:11.
(b) Kieran’s savings are 9/11 of the total savings.
(c) Simon’s savings are S÷11S/2=2/11 of total savings (or simply subtract 9/11 from 1).
(d) K-S=28, 9/11-2/11=7/11 of the total savings, so 7/11 of the total savings is $28 and total savings is 11/7×28=$44.
CHECK
Kieran has 9/11 of $44 which is $36 and Simon has $8. 36/8=9/2 so the ratio is correct.
Simon has $28 less than Kieran and 36-8=28, which is correct.