Question

What is the equation of the vertical asymptote of g(x)=4 log 3 (x−2)+5 ?

Answer 1

That would be  when x = 2 which will make it log3 = 0

Answer x = 2

Answer 2

Answer:

x = 2

Step-by-step explanation:

Assuming the function is

$g(x) = 4 \log_{3} (x - 2) + 5$

All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.

That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor  the vertical shift made by the +5.

In this case the argument is x - 2, then the vertical asymptote is:

x - 2 = 0

x = 2