Question

Identify the vertical asymptote(s) of each function. Check all of the boxes that apply. f(x)=x-8/x^2-3x+2


x = -8


x = -2


x = -1


x = 1


x = 2


x = 8

Nevermind the answer was x=1 and x=2. If anyone is wondering how to do it you can put the denominator in desmos and where the 2 points hit the x axis is your answer.

Answer 1

Nevermind the answer was x=1 and x=2. If anyone is wondering how to do it you can put the denominator in desmos and where the 2 points hit the x axis is your answer.

Answer 2

Answer:

x=1 and x=2

Step-by-step explanation:

$f(x)=\frac{x-8}{x^2-3x+2}$

To find the vertical asymptote , we set the denominator =0 and solve for x

$x^2-3x+2=0$

Factor the left hand side of the equation

Product is 2 and sum is -3

the factors are -2 and -1

$(x-2)(x-1)=0$

Set each factor =0 and solve for x

$x-2=0 , x=2$

$x-1=0 , x=1$

the vertical asymptote at x=1 and x=2